Problem C: Reversed Numbers
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The Antique Comedians of Malidinesia prefer comedies to tragedies.
Unfortunately, most of the ancient plays are tragedies. Therefore the
dramatic advisor of ACM has decided to transfigure some tragedies into
comedies. Obviously, this work is very hard because the basic sense of
the play must be kept intact, although all the things change to their
opposites. For example the numbers: if any number appears in the
tragedy, it must be converted to its reversed form before being accepted
into the comedy play.

Reversed number is a number written in arabic numerals but the order of
digits is reversed. The first digit becomes last and vice versa. For
example, if the main hero had 1245 strawberries in the tragedy, he has
5421 of them now. Note that all the leading zeros are omitted. That
means if the number ends with a zero, the zero is lost by reversing
(e.g. 1200 gives 21). Also note that the reversed number never has any
trailing zeros.

ACM needs to calculate with reversed numbers. Your task is to add two
reversed numbers and output their reversed sum. Of course, the result is
not unique because any particular number is a reversed form of several
numbers (e.g. 21 could be 12, 120 or 1200 before reversing). Thus we
must assume that no zeros were lost by reversing (e.g. assume that the
original number was 12).

Input 
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The input consists of N cases. The first line of the input contains
only positive integer N. Then follow the cases. Each case consists of
exactly one line with two positive integers separated by space. These
are the reversed numbers you are to add. Numbers will be at most 200
characters long.

Output 
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For each case, print exactly one line containing only one integer - the
reversed sum of two reversed numbers. Omit any leading zeros in the output.

Sample Input 
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3
24 1
4358 754
305 794

Sample Output 
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34
1998
1